5x^2-972=0

Solution for 5x^2-972=0 equation:

5x^2-972=0

a = 5; b = 0; c = -972;
Δ = b2-4ac
Δ = 02-4·5·(-972)
Δ = 19440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19440}=\sqrt{1296*15}=\sqrt{1296}*\sqrt{15}=36\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{15}}{2*5}=\frac{0-36\sqrt{15}}{10}
=-\frac{36\sqrt{15}}{10}
=-\frac{18\sqrt{15}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{15}}{2*5}=\frac{0+36\sqrt{15}}{10}
=\frac{36\sqrt{15}}{10}
=\frac{18\sqrt{15}}{5}
$